How To Find Index Of List Item In Swift

To find the index of a list item, you can use the firstIndex or lastIndex function:

let arr = [1, 2, 3, 4, 1]

let firstIndex = arr.firstIndex(of: 1) // 0
let lastIndex = arr.lastIndex(of: 1) // 4

If you have an class or want to check a condition, you can use the where instead of of.

let arr = [1, 2, 3, 4, 1]

let firstIndex = arr.firstIndex(where: { $0 % 2 == 0} )
let lastIndex = arr.lastIndex(where: { $0 % 2 == 0} )
print(firstIndex)
print(lastIndex)

The above code checks for even numbers and prints:

Optional(1)
Optional(3)

Note that firstIndex and lastIndex return optionals and can be nil if the element is not found.

You could do the same with a custom object, for example:

let firstIndex = personArray.firstIndex($0.name == "Eddy")

Get All Indexes Of Filtered Item In Array

To do this, it’s best to create custom array extension:

extension Array where Element: Equatable {
    func indexes(of element: Element) -> [Int] {
        return self.enumerated().filter({ element == $0.element }).map({ $0.offset })
    }
}

Then you can call it like so:

let arr = [1, 2, 3, 4, 1]
arr.indexes(of: 1)
print(arr)

This prints:

[0, 4]
If you liked this post and want to learn more, check out The Complete iOS Developer Bootcamp. Speed up your learning curve - hundreds of students have already joined. Thanks for reading!

Eddy Chung

I teach iOS development on ZeroToAppStore.com.

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